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A ball of mass m is dropped from height ‘h’ the time taken by the ball to reach the ground is [ take ‘g’ as acceleration due to gravity]
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Height= 1/2 × acceleration due to gravity × time2 + intial speed × time 

The initial speed is zero because the ball is dropped and not thrown. 

Therefore, we can solve for time: 

 Time = √((2 × height) / 10))=√(height/5)

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