Time to reach the peak (t)=6.25/2=3.125s
When the ball reaches to peak point, the final velocity will be zero. v=0m/s .
Here, the acceleration of ball is a=−g=−9.8m/s 2
"u" is the initial velocity of the baseball.
Using v=u+at,
0=u+(−9.8)(3.125)
u=30.625m/s
"h" is the height reached by ball.
Using v2−u2=2ah
02 −(30.625)2=2(−9.8)h
h=47.85m