Coin pair
H :stands for head
T:stands for tail
sample space S
S = {HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT}
S = 16
The case of getting at least two heads:C
C= {HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, THHH, THHT, THTH, TTHH}
C = 11
The probability of getting at least 2 heads when a pair of coin is tossed four times =c/s=11/16.